A) 288
B) 290
C) 130
D) 286
Correct Answer: C
Solution :
Let the numbers be 13x and 13y where x and y are co-prime. Then, product of numbers \[=HCF\times LCM\] \[\Rightarrow \] \[13x\times 13y=13\times 273\] \[\Rightarrow \] \[xy=\frac{13\times 273}{13\times 13}\] \[\Rightarrow \] \[xy=21=3\times 7\] \[\therefore \] Numbers are \[3\times 13=39\] and \[7\times 13=91\] \[\therefore \] Required sum =\[39+91=130\]You need to login to perform this action.
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