A) \[2\sqrt{3}\,cm\]
B) \[2\sqrt{6}\,cm\]
C) 2 cm
D) 3 cm
Correct Answer: A
Solution :
Area of original circle \[=\pi \times {{(6)}^{2}}=36\,c{{m}^{2}}\] After trisection, the area of the smallest circle \[=\frac{1}{3}\times 36\pi \] \[=12\pi =\pi \times {{(2\sqrt{3})}^{2}}\] \[\therefore \] Required radius \[=2\sqrt{3}\,cm\]You need to login to perform this action.
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