A) 25%
B) 33.33%
C) 50%
D) 75%
Correct Answer: C
Solution :
Let total quantity \[=x\,L\] Quantity of milk \[=\frac{2x}{5}L\] And quantity of water \[=\frac{3x}{5}L\] \[\therefore \] Since 50% of mixture is replaced by wafer. \[\therefore \] Remaining quantity of milk \[=\frac{2x}{5}\times \frac{1}{2}=\frac{x}{5}L\] And quantity of water \[=\frac{3x}{10}+\frac{x}{2}\] \[=\frac{8x}{10}=\frac{4x}{5}L\] Hence the concentration of the solution is reduced by 50%You need to login to perform this action.
You will be redirected in
3 sec