A) 15 m West
B) 30 m East
C) 30 m West
D) 45 m East
Correct Answer: D
Solution :
The movements of Rasik from A to F are as shown in Figure. Since CD = AB + EF, so F lies in line with A. \[\therefore \] Rasik's distance from original position A \[=AF=(AG+GF)\] \[=(BC+DE)=(30+15)m=45\,m.\] Also, F lies to the East to A.You need to login to perform this action.
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