A) 1.98
B) 1.09
C) 1
D) 0
Correct Answer: D
Solution :
Let \[a=0.98,\]\[b=0.01,\]\[c=-1\] But, \[a+b+c=0.98+0.01-1=0\] \[\therefore \] \[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}-3abc=0\] \[\Rightarrow \] \[{{(0.98)}^{2}}+{{(0.01)}^{2}}-1+3\times 0.98\times 0.02=0\]You need to login to perform this action.
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