A) 12
B) 20
C) 24
D) 48
Correct Answer: D
Solution :
Let second number \[=x\] \[\therefore \] first number \[=2x\] And third number \[=4x\] According to question, \[56=\frac{2x+x+4x}{3}\] \[\Rightarrow \] \[x=\frac{56\times 3}{7}=74\] \[\therefore \] Requited difference \[=4x-2x=2x=2\times 24=48\]You need to login to perform this action.
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