A) \[11\frac{5}{11}\] min
B) \[11\frac{109}{121}\] min
C) \[11\frac{100}{121}\] min
D) \[11\frac{4}{11}\] min
Correct Answer: B
Solution :
60 min will be gained by the minute hand in \[65\frac{5}{11}\] min. Thus, the hands of a correct dock coincide every \[65\frac{5}{11}\] min. But the hands of the clock in question coincide every 66 min. \[\therefore \] In every 66 min, the clock in question loses \[\frac{6}{11}\] min. In 24 h, the clock in question loses \[=\left( \frac{6}{11}\times \frac{1}{66}\times 24\times 60 \right)\min =\left( \frac{1440}{121} \right)\min =11\frac{109}{121}\min \]
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