A) 24
B) 22
C) 21
D) 11
Correct Answer: A
Solution :
When the unit's digit of two numbers be an even number and 5 of 0, then their product gives zero at unit's place. \[\therefore \] Number of zeros in the product of 1, 2, 3,.... and 100 \[=\frac{100}{5}+\frac{100}{{{5}^{2}}}=20+4=24\]You need to login to perform this action.
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