A) Rs. 520
B) Rs. 572
C) Rs. 600
D) Rs. 625
Correct Answer: D
Solution :
\[A=P{{\left( 1+\frac{R}{100} \right)}^{T}}\] \[\Rightarrow \] \[676=650\left( 1+\frac{r}{100} \right)\] \[\Rightarrow \] \[1+\frac{r}{100}=\frac{676}{650}\] \[\Rightarrow \] \[\frac{r}{100}=\frac{676}{650}-1\] \[=\frac{26}{650}\] \[\Rightarrow \] \[r=\frac{26}{650}\times 100=4\] \[\therefore \] \[650=P{{\left( 1+\frac{4}{100} \right)}^{1}}\] \[\Rightarrow \] \[650=P\times \frac{26}{25}\] \[\Rightarrow \] \[P=\frac{650\times 25}{26}=Rs.\,625\]You need to login to perform this action.
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