A) 0.014
B) 1.4
C) 1
D) 1.4
Correct Answer: D
Solution :
\[\frac{{{(6.25)}^{\begin{matrix} 1 \\ 2 \\ \end{matrix}}}\times {{(0.0144)}^{\begin{matrix} 1 \\ 2 \\ \end{matrix}}}+1}{{{(0.027)}^{\begin{matrix} 1 \\ 3 \\ \end{matrix}}}\times {{(81)}^{\begin{matrix} 1 \\ 4 \\ \end{matrix}}}}\] \[=\frac{2.5\times 0.12+1}{0.3\times 3}=\frac{1.3}{0.9}=\frac{13}{9}=1\frac{4}{9}=1.\overline{4}\]You need to login to perform this action.
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