A) 5th, 12th 19th, 26th
B) 4th, 11th, 18th, 25th
C) 3rd, 10th, 17th, 24th
D) None of the above
Correct Answer: B
Solution :
We shall find the data on 1st March, 2003. 1st March, 2003 = (2000 yr + Period from 1.1.2003 to 1.3.2003) odd days in 2000 yr = 0 2 yr = 2 ordinary years = 2 odd days. Jan Feb March \[(30+28+1)=60\] days = (8 weeks + 4 days) \[=4\]odd days. Thus, Total number of odd days. \[=(0+2+4)=6\] odd days. Thus, 1st March, 2003 was Saturday. So, 4th, 11th, 18th and 25 March 2003 were Tuesday.
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