A) 4
B) \[\frac{1}{4}\]
C) 270
D) \[\frac{1}{270}\]
Correct Answer: B
Solution :
Let 137 \[=a\] and \[133=b\] \[\therefore \] Expression \[=\frac{a\times a+a\times b+b\times b}{a\times a\times a-b\times b\times b}\] \[=\frac{{{a}^{2}}+ab+{{b}^{2}}}{{{a}^{3}}-{{b}^{3}}}\] \[=\frac{{{a}^{2}}+ab+{{b}^{2}}}{(a-b)({{a}^{2}}+ab+{{b}^{2}})}\] \[=\frac{1}{a-b}\] \[=\frac{1}{137-133}=\frac{1}{4}\]
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