A) \[{{6}^{2/3}}\]
B) 6
C) \[3\frac{1}{2}\]
D) 3
Correct Answer: D
Solution :
Let \[x=\sqrt{6+\sqrt{6+\sqrt{6+.............}}}\] or \[x=\sqrt{6+x}\] or \[{{x}^{2}}=6+x\] or \[{{x}^{2}}-x-6=0\] or \[{{x}^{2}}-3x+2x-6=0\] or \[x(x-3)+2(x-3)=0\] or \[(x+2)(x-3)=0\] \[\therefore \] \[x=-\,2\] and x = 3You need to login to perform this action.
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