A) 23
B) 7
C) 13
D) 169
Correct Answer: A
Solution :
Let the numbers be a and b. According to the question, \[ab=120\] ? (i) \[{{a}^{2}}+{{b}^{2}}=289\] ? (ii) \[\therefore \] \[{{(a+b)}^{2}}={{a}^{2}}+{{b}^{2}}+2ab\] \[=289\times 2\times 120=289+240=529\] \[\therefore \] \[a+b=\sqrt{529}=23\]You need to login to perform this action.
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