A) 11.732
B) 13.928
C) 12.928
D) 13.925
Correct Answer: B
Solution :
Expression\[=\frac{2+\sqrt{3}}{2-\sqrt{3}}=\frac{(2+\sqrt{3})(2+\sqrt{3})}{(2-\sqrt{3})(2+\sqrt{3})}\] [On rationalising the denominator] \[=\frac{{{(2+\sqrt{3})}^{2}}}{4-2}={{(2+\sqrt{3})}^{2}}\] \[={{2}^{2}}+{{(\sqrt{3})}^{2}}+2\times 2\times \sqrt{3}\] \[=4+3+4\sqrt{3}\] \[=7+4\times 1.732\] \[=7+6.928\] \[=13.928\]You need to login to perform this action.
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