A) 100
B) 180
C) 200
D) 400
Correct Answer: C
Solution :
Let the number of Student in three classes be 2x, 3x and 5x respectively. Due to increase of 40 students in each class we have \[\frac{2x+40}{3x+40}=\frac{4}{5}\] \[\Rightarrow \] \[10x+200=12x+160\] \[\Rightarrow \] \[2x=40\] \[\Rightarrow \] \[x=20\] \[\therefore \] Total number of students initially \[=2x+3x+5x=10x\] = 200You need to login to perform this action.
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