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SSC Sample Paper SSC-CGL TIER - I Sample Test Paper-10

  • question_answer
    Let f(x) = \[a{{x}^{2}}+bx+2\] and g(x) = \[b{{x}^{2}}+ax+1.\] If \[x-2\] is a factor of (x) but leaves the remainder -15 when it divides g(x), then the value of b is:

    A) 5                                 

    B) -5

    C) 2                                 

    D) -2

    Correct Answer: B

    Solution :

    \[\therefore \]\[(x-2)\] is factor off (x). \[\Rightarrow \,\,\,\,\,a{{\left( 2 \right)}^{2}}+b\times 2+2=0\] \[4a+2b+2=0\]                 ... (i) when\[~x-2\] divides g(x) it leaves remainder - 15. \[\Rightarrow \]     \[(x-2)\] is a factor of g(x) - (-15) \[\Rightarrow \]     \[b{{\left( 2 \right)}^{2}}+a\times 2+1+15=0\] 4b + 2a + 16 = 0              ... (ii) On solving (i) & (ii), we have b = - 5


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