A) \[384square\text{ }m\]
B) \[284\sqrt{6}~square\text{ }m\]
C) \[484square\text{ }m\]
D) \[384~\sqrt{6}square\text{ }m\]
Correct Answer: D
Solution :
Sides of triangular park are \[\frac{5}{18}\times 144,\frac{6}{18}\times 144,\frac{7}{18}\times 144\,\,cm\] 40, 48, 56 cm, S (semi-perimeter) = \[\frac{40\text{ }+\text{ }48\text{ }+\text{ }56}{2}=72\] Area of triangle = \[\sqrt{72\left( 72-40 \right)\left( 72-48 \right)\left( 72-56 \right)}\] = \[\sqrt{72\times 32\times 24\times 16}\] = \[\sqrt{2\times 36\times 2\times 16\times 4\times 6\times 4\times 4}\] = \[6\times 2\times 4\times 2\times 4\times \sqrt{6}=\]
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