A) 5
B) -5
C) 2
D) -2
Correct Answer: B
Solution :
\[\therefore \]\[(x-2)\] is factor off (x). \[\Rightarrow \,\,\,\,\,a{{\left( 2 \right)}^{2}}+b\times 2+2=0\] \[4a+2b+2=0\] ... (i) when\[~x-2\] divides g(x) it leaves remainder - 15. \[\Rightarrow \] \[(x-2)\] is a factor of g(x) - (-15) \[\Rightarrow \] \[b{{\left( 2 \right)}^{2}}+a\times 2+1+15=0\] 4b + 2a + 16 = 0 ... (ii) On solving (i) & (ii), we have b = - 5You need to login to perform this action.
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