A) 1 : 2
B) 1 : 3
C) 1 : 4
D) 2 : 3
Correct Answer: A
Solution :
Diagonal of the 1st square = 10 cm Its side = \[\frac{10}{\sqrt{2}}=5\sqrt{2}cm\] Its area = \[{{\left( 5\sqrt{2} \right)}^{2}}=50\,c{{m}^{2}}\] Area of the another square = \[{{10}^{2}}=100\,c{{m}^{2}}\] \[\therefore \] Required ratio - 50: 100 = 1: 2You need to login to perform this action.
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