A) \[\frac{4}{5}\]
B) \[\frac{5}{4}\]
C) \[\frac{3}{4}\]
D) \[\frac{3}{5}\]
Correct Answer: B
Solution :
BP and CQ are medians of right angle\[\Delta ABC\], right angled at A. Now, \[B{{P}^{2}}={{\left( \frac{1}{2}AC \right)}^{2}}~+\text{ }A{{B}^{2}}\] and\[C{{Q}^{2}}=A{{C}^{2}}+{{\left( \frac{1}{2}AB \right)}^{2}}\] \[\Rightarrow \] \[B{{P}^{2}}~+\text{ }C{{Q}^{2}}=\frac{5}{4}(A{{B}^{2}}~+\text{ }A{{C}^{2}})\] \[\Rightarrow \] \[B{{P}^{2}}+\text{ }C{{Q}^{2}}=\frac{5}{4}B{{C}^{2}}\] \[(\therefore A{{C}^{2}}+A{{B}^{2}}~=\text{ }B{{C}^{2}})\] \[\Rightarrow \]\[\]You need to login to perform this action.
You will be redirected in
3 sec