A) \[\sqrt{3}\]
B) 2
C) 4
D) \[2\sqrt{3}\]
Correct Answer: B
Solution :
\[sec\theta ~+tan\theta ~=\text{ }2+\sqrt{3}\] \[sec\theta -tan\theta ~=\text{ }2-\sqrt{3}\] \[[Use\text{ }se{{c}^{2}}~\theta -\text{ }ta{{n}^{2}}\theta ~=1]\] \[\Rightarrow \]\[\]You need to login to perform this action.
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