A) 2 m.
B) \[\frac{5}{2}m.\]
C) \[\frac{3}{2}m.\]
D) \[\sqrt{3}m.\]
Correct Answer: C
Solution :
Suppose x m be the side of the equilateral triangle Case I: Area = \[\frac{\sqrt{3}}{4}{{x}^{2}}{{m}^{2}}\] Case II: New side = \[\left( x+1 \right)m\] New area = \[\frac{\sqrt{3}}{4}{{(x+1)}^{2}}{{m}^{2}}\] Now, \[\frac{\sqrt{3}}{4}{{(x+1)}^{2}}-\frac{\sqrt{3}}{4}{{x}^{2}}=\sqrt{3}\] \[\frac{\sqrt{3}}{4}[(2x+1)\times 1]=\sqrt{3}\] \[2x+1+4\Rightarrow \]
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