A) 4
B) 6
C) 8
D) 10
Correct Answer: A
Solution :
\[\therefore \] PQ\[ll\]BC \[\Rightarrow \,\,\,\,\frac{AP}{AB}=\frac{AQ}{AC}\Rightarrow \frac{AP}{AQ}=\frac{AB}{AQ}\] \[\Rightarrow \,\,\,\,\frac{AP}{2}=\frac{12}{AC}\Rightarrow \,\,\,AC\,\,.\,\,AP=24\] \[\Rightarrow \] (AQ + QC). QC = 24 \[\Rightarrow \] (2 +QC). QC = 24 \[\Rightarrow \]QC\[^{2}\]+ 2QC ? 24 = 0 \[\Rightarrow \](QC + 6) (QC - 4) = 0 \[\Rightarrow \]QC = \[\]You need to login to perform this action.
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