A) 300
B) 500
C) 700
D) 400
Correct Answer: D
Solution :
Let the maximum marks in the examination = x then, \[30%\text{ }of\,x+12=40%\text{ }of\,x-28\] = \[\left( \frac{40}{100}-\frac{30}{100} \right)x=40\Rightarrow \]You need to login to perform this action.
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