A) \[\times ,\div ,-,=\]
B) \[+,-,\div ,=\]
C) \[-,-,+,=\]
D) \[-,\times ,\div ,=\]
Correct Answer: A
Solution :
Solving from the choices: [a] Inserting the operators (x,\[\div \],-, =) We get, \[\][Use BODMAS' rule] 5 ? 5 = 0 \[\Rightarrow \]0 = 0 [b] Inserting the operators (+, -,\[\div \], =) We get, 5 + 3 ? 3 \[\div \] 5 = 0 [Use BODMAS' rule] 5 + 3 ? 6 = 0 \[\Rightarrow \]8 ? 6 = 0 \[\Rightarrow \]7.4\[\ne \]0 [c] Inserting the operator (\[\div \], -, +, =) We get. 5 - 3 - 3 + 5 = 0 [Use BODMAS' rule] 2 + 2 = 0 \[\Rightarrow \] 4\[\ne \]0 [d] Inserting the operators (-, \[\times \], \[\div \], =) We get, 5 - 3 \[\times \] 3 \[\div \] 5 = 0 [Use ?BODMAS' rule] 5 - 3 \[\times \]0.6 = 0 \[\Rightarrow \] 5 - 1.8 = 0 \[\Rightarrow \] 3.2 \[\ne \] 0
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