question_answer

The angle of elevation of top of a tower from a distance 200 m from its foot is 45°. Height of the tower is:

A)  \[200~m\]

B)  \[\frac{200}{\sqrt{3}}m\]

C)  \[200~\sqrt{3}m\]

D)  None of these

Correct Answer: A

Solution :

 Let height of tower h m. From DABC, tan 45\[^{\circ }\]= \[\frac{h}{200}\] 1 =\[\frac{h}{200}\]\[\Rightarrow \]\[\]