A) -1
B) 0
C) 1
D) 2
Correct Answer: C
Solution :
\[x=a\,\sec \theta \Rightarrow \frac{x}{a}=\sec \theta \] ... (1) Similarly,\[\frac{y}{b}=\tan \theta \] ... (2) Squaring and subtracting them \[{{\left( \frac{x}{a} \right)}^{2}}-{{\left( \frac{y}{b} \right)}^{2}}={{\sec }^{2}}\theta -{{\tan }^{2}}\theta =\]You need to login to perform this action.
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