A) \[3,\frac{1}{3}\]
B) \[3,-\frac{1}{3}\]
C) \[-3,\frac{1}{3}\]
D) \[-3,-\frac{1}{3}\]
Correct Answer: A
Solution :
Let the numbers are x and\[\frac{1}{x}\]. Then \[x+\frac{1}{x}=\frac{10}{3}\Rightarrow \frac{{{x}^{2}}+1}{x}=\frac{10}{3}\] \[\Rightarrow \] \[3{{x}^{2}}-10x+3=0\] \[\Rightarrow \] \[3{{x}^{2}}-9x-x+3=0\] \[\Rightarrow \] \[3x(x-3)-1(x-3)=0\] \[\Rightarrow \] \[(3x-1)(x-3)=0\]\[\Rightarrow \]You need to login to perform this action.
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