A) \[\frac{5}{4}\]
B) \[\frac{6}{5}\]
C) \[\frac{25}{31}\]
D) \[\frac{31}{42}\]
Correct Answer: C
Solution :
\[\frac{x}{y}=\frac{7}{5}\] \[\frac{5x-2y}{3x+2y}=\frac{5.\frac{x}{y}-2}{3.\frac{x}{y}+2}=\frac{5\times \frac{7}{5}-2}{3\times \frac{7}{5}+2}=\]You need to login to perform this action.
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