A) 2 liter
B) 1 liter
C) \[1\frac{1}{2}~liter\]
D) \[~\frac{3}{4}liter\]
Correct Answer: A
Solution :
Suppose the concentration of acids in two containers A and B are x% and y% respectively. Quantity of Acid in A = \[6\times \frac{x}{100}\] Quantity of Acid in B = \[3\times \frac{y}{100}\] Suppose k. litre acid is emptied from each container, then Total acid in A =\[\frac{6x}{100}-\frac{k\times x}{100}+\frac{k\times y}{100}\] Total acid in B = \[\frac{3y}{100}-\frac{k\times y}{100}+\frac{kx}{100}\] According to questions - \[\frac{\frac{6x}{100}-\frac{kx}{100}+\frac{ky}{100}}{6}\times 100=\frac{\frac{3y}{100}-\frac{ky}{100}+\frac{kx}{100}}{3}\times 100\] \[\frac{6x}{100}-\frac{kx}{100}+\frac{ky}{100}=\frac{6y}{100}-\frac{2ky}{100}+\frac{2kx}{100}\] \[\frac{6}{100}(x-y)=\frac{3k}{100}(x-y)\Rightarrow k=\mathbf{2}\text{ }\mathbf{litres}\]You need to login to perform this action.
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