A) 75
B) 85
C) 91
D) 100
Correct Answer: D
Solution :
\[\Rightarrow \] x = 3 \[\therefore \] y = 4 Now, \[4{{x}^{2}}+ {{y}^{2}}+ 4xy\] \[=~~{{\left( 2x+ y \right)}^{2}}= {{\left( 2 {{x}^{3}}+ 4 \right)}^{2}}=100\]You need to login to perform this action.
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