A) 18 units
B) 24 units
C) 48 units
D) Cannot be determined due to
Correct Answer: B
Solution :
Perimeter of A PQR = 1 + 2 + 3 = 6 units Now, \[\Delta \]DEF, = \[\frac{PR}{DF}=\frac{1}{2}=\frac{PQ}{FE}\] So, 2PQ = FE Similarly, DF = 2PR and DE = 2QP \[\therefore \] Perimeter of \[\Delta \]DEF = 2 x 6 = 12 units Similarly, perimeter of \[\Delta \]ABC \[= 2 \times Perimeter of\]\[\Delta \]DEF \[= 2 \times 12 =124 units\]You need to login to perform this action.
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