A) \[90{}^\circ -x\]
B) \[80{}^\circ -\angle POR\]
C) \[180{}^\circ -2\angle POR\]
D) \[90{}^\circ -\angle POR\]
Correct Answer: C
Solution :
OS is on POQ So, \[\angle POS+\angle SOQ=180{}^\circ \text{ }but\angle POS=x\] \[x+\angle SOQ\text{ }=180{}^\circ ~\Rightarrow \angle SOQ=180{}^\circ -x\] \[=180{}^\circ -2\angle POR\](OR is bisector of)You need to login to perform this action.
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