A) 54
B) 88
C) 76
D) 72
Correct Answer: C
Solution :
\[{{(a+b+c)}^{2}}={{a}^{2}}+{{b}^{2}}+{{c}^{2}}+2(ab+bc+ca)\] \[\begin{align} & \Rightarrow \frac{{{16}^{2}}-104}{2}=ab+bc+ca \\ & \Rightarrow \frac{256-104}{2}=ab+bc+ca \\ \end{align}\] \[\therefore \] 76 = \[ab+bc+ca\]You need to login to perform this action.
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