A) 0
B) \[\frac{1}{2}\]
C) 1
D) 2
Correct Answer: C
Solution :
In \[\Delta \]ABC, if \[\angle \]C is 90°, then \[\angle \]A + \[\angle \]B = 180° - 90° = 90° Now, cos (A + B) + sin (A + B) \[= cos 90{}^\circ + sin 90{}^\circ \] = 0 + 1 = [1]You need to login to perform this action.
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