A) \[80c{{m}^{2}}\]
B) \[84c{{m}^{2}}\]
C) \[88c{{m}^{2}}\]
D) \[90c{{m}^{2}}\]
Correct Answer: B
Solution :
Semi-perimeter of triangle = \[\frac{a+b+c}{2}\] = \[\frac{7+24+25}{2}=\frac{56}{2}=28\,\,cm\] Area of circle = Area of triangle = \[\sqrt{s(s-a)(s-b)(s-c)}\] = \[\sqrt{28(28-7)(28-24)(28-25)}\] = \[\sqrt{28\times 21\times 4\times 3}=\sqrt{7056}=84c{{m}^{2}}\]You need to login to perform this action.
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