A) 15
B) 12
C) 9
D) 6
Correct Answer: B
Solution :
Suppose there were x friends initially, share on each on food = Rs \[\frac{108}{x}\] By question \[\frac{108}{x-3}-\frac{108}{x}=3\] \[\Rightarrow \,\,\,\,\,\,\frac{x-\left( x-3 \right)}{x(x-3)}=\frac{3}{108}\] \[\Rightarrow \,\,\,\,\,\,\frac{3}{{{x}^{2}}-3x}=\frac{3}{108}\] \[\Rightarrow \,\,\,\,\,\,{{x}^{2}}-3x-108=0\] \[\Rightarrow \,\,\,\,\,\left( x-12 \right)\left( x+9 \right)=0\,\,\therefore \,\,x=\mathbf{12}\]You need to login to perform this action.
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