A) 7 : 19
B) 1 : 2
C) 25 : 47
D) 67 : 91
Correct Answer: C
Solution :
Suppose glasses A, B and C contains 2, 3 and 41 mixtures Total quantity of water = \[\frac{1}{6}\times 2+\frac{3}{8}\times 3+\frac{5}{12}\times 4=\frac{25}{8}l\] Total quantity of alcohol = \[\frac{5}{6}\times 2+\frac{5}{8}\times 3+\frac{7}{12}\times 4=\frac{47}{8}l\] \[\therefore \] Required Ratio = \[\frac{25}{8}:\frac{47}{8}=\] 25: 47You need to login to perform this action.
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