A) 0
B) 1
C) 4
D) None of the above
Correct Answer: A
Solution :
\[x+y=2\] (given) Now, \[\Rightarrow \,\,\,\,\,xy\left( x-y \right)+{{x}^{2}}\left( x-y \right)+{{y}^{2}}\left( 2-y \right)\] \[\Rightarrow \,\,\,\,\,xy\left( x-y \right)+{{x}^{2}}\left( -y \right)+{{y}^{2}}\times x\] \[[\therefore \,\,\,\,\,x+y=2]\] \[\Rightarrow \,\,\,\,\,\,xy[x-y-x+y]\Rightarrow xy[0]\] = 0You need to login to perform this action.
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