A) 2
B) 3
C) 4
D) 5
Correct Answer: B
Solution :
Let r be the radius of the cylindrical rod, its height = 4r its volume = \[\pi \,\,\times \,\,{{r}^{2}}\times 4r=4\pi {{r}^{3}}\] \[\Rightarrow \] volume of the 1 spherical ball = \[\frac{3}{4}\pi {{r}^{3}}\] Number of balls = \[\frac{Volume\text{ }of\text{ }cylindrical\text{ }rod}{Volume\text{ }of\text{ }1\text{ }ball}\] = \[\frac{4\pi {{r}^{3}}}{\frac{4}{3}\pi {{r}^{3}}}=\]You need to login to perform this action.
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