Year | Number of tourists |
2008 | 12 |
2009 | 13.5 |
2010 | 14.5 |
2011 | 16 |
2012 | 17.6 |
A) 2009
B) 2010
C) 2011
D) 2012
Correct Answer: A
Solution :
% increase in 2009 = \[\frac{1.5}{12}\times 100=12.5%\] % increase in 2010 = \[\frac{1\times 100}{13.5}=7.40%\] % increase in 2011 = \[\frac{1.5}{14.5}\times 100=10.34%\] % increase in 2012 \[\frac{1.6}{16}\times 100=10%\] \[\therefore \] maximum % increase occurs in 2009 over 2008You need to login to perform this action.
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