A) \[x-3\]
B) \[x-5\]
C) \[x+3\]
D) \[x+1\]
Correct Answer: A
Solution :
By Factor Theorem. If \[f(a)=0,\] then \[(x-a)\]is a factor of \[f(x).\] \[\therefore \,f(3)={{3}^{3}}+{{3}^{2}}-17\times 3+15\] \[=27+9-51+15=0\] \[\therefore (x-3),\] is a factor of \[f(x).\] Remember: \[f(5)\,\cancel{=}0:f(-3)\cancel{=}0:f(-1)\cancel{=}0\]You need to login to perform this action.
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