A) 59
B) 59.5
C) 60
D) 60.5
Correct Answer: C
Solution :
Sum of total number of 8 students in exam \[=8\times 51=408\] Sum of total number of 9 students in exam \[=\text{ }9\times 68\text{ }=712\] \[\therefore \] Required average \[=\frac{408+712}{17}\] \[=\frac{1020}{17}\approx 60\]You need to login to perform this action.
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