A) 1: 2
B) 2: 1
C) 4: 1
D) 1: 4
Correct Answer: C
Solution :
Let PQ be the perpendicular distance between the two parallel sides AB and CD. So, \[\frac{area\,\,of\,\Delta \,AOB}{area\,\,of\,\Delta \,COD}\] \[=\,\,\,\frac{\frac{1}{2}AB\times OP}{\frac{1}{2}CD\times OQ}[\because \,OP=\,2OQ]\] \[=\frac{2CD\times 2OQ}{CD\times OQ}=\frac{4}{1}\]You need to login to perform this action.
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