A) \[2:1\]
B) \[\sqrt{3}:1\]
C) \[\sqrt{5}:1\]
D) \[4:1\]
Correct Answer: B
Solution :
Here let O. O' be the centres of the circle. As the centre of each lies on the circumference of the other, the two circles will have the same ra-dius ame radius. Let it be r. \[\therefore \,OC\,=O'C=\frac{r}{2}\] \[\therefore \,\,AC=\sqrt{O{{A}^{2}}-O{{C}^{2}}}\] \[=\sqrt{{{r}^{2}}-\frac{{{r}^{2}}}{4}}=\frac{\sqrt{3}}{2}r\] \[AB=\sqrt{3\,}\,\,r\] Hence \[\frac{common\text{ }chord}{radius}\] \[=\sqrt{3}\,\,r:r=\sqrt{3}:1\]You need to login to perform this action.
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