A) \[15\sqrt{3}\,m\]
B) \[\frac{15}{\sqrt{3}}\,m\]
C) \[15\,m\]
D) \[15\,(\sqrt{3}+1)m\]
Correct Answer: C
Solution :
Height of hill \[=(10+a)\,m.\] In \[\Delta \,EDA,\]we get \[\tan \,30{}^\circ =\frac{a}{x}\Rightarrow x=a\sqrt{3}\,\,m\] ??(i) In \[\Delta ECB,\] \[\tan \,60{}^\circ =\frac{10+a}{x}\] \[\Rightarrow \,\,\sqrt{3}=\frac{10+a}{x}\Rightarrow x=\frac{10+a}{\sqrt{3}}\] \[a\sqrt{3}=\frac{10+a}{\sqrt{3}}\] (from equation (i)) \[3a=10+a\Rightarrow 2a=10\Rightarrow a=5\text{ }m\] Height of hill \[=\left( 10+5 \right)=\]You need to login to perform this action.
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