A) \[\frac{1}{2}\]
B) \[\frac{1}{3}\]
C) \[\frac{1}{4}\]
D) \[\frac{1}{6}\]
Correct Answer: D
Solution :
\[\frac{4\,\sin \theta -\cos \theta }{4\sin \theta +9\cos \theta }\] On dividing both numerator and denominator by \[cos\text{ }\theta ,\]we get- \[=\,\,\,\frac{4\tan \theta -1}{4\tan \theta +9}=\frac{3-1}{3+9}=\frac{2}{12}=\]You need to login to perform this action.
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