A) 100 days
B) 75 days
C) 50 days
D) 25 days
Correct Answer: D
Solution :
Part of the field graze by 4 goats in 1 day \[=\frac{1}{50}\] Part of field graze by 1 goat in 1 day \[=\frac{1}{50\times 4}=\frac{1}{200}\] \[4g\text{ }=\text{ }6s\] (Here, g = goats, s = Sheep) \[=1s\,=\frac{4}{6}g=\frac{2}{3}g\] Now, \[2g+9s=2g+9\times \frac{2}{3}g\Rightarrow 2g+6g=8g\] \[\therefore \] 8 goats can graze the field in \[=\,\,\,\frac{1}{\frac{8}{200}}=\]
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