A) \[78:7:20\]
B) \[9:1:2\]
C) \[78:20:7\]
D) \[9:2:1\]
Correct Answer: A
Solution :
Suppose Ist bag contains 35 kg mixture and 2nd bag contains 70 kg mixture. Quantity of dry cement in bag Ist \[=\frac{4}{5}\times 35=28\,kg\] Quantity of sand in bag 1st \[=\frac{1}{5}\times 35=7kg\] Quantity of dry cement in bag II \[=\frac{5}{7}\times 70=50\,kg\] Quantity of concrete in bag \[=\frac{2}{7}\times 70=20\,kg\] \[\therefore \] Required ratio \[=(28+50):7:20\] \[\mathbf{=}\,\,\]You need to login to perform this action.
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